How to find all pairs of digits that sum to a specific number
How to find all pairs of digits that sum to a specific number
I am trying to write a Python function that gets a number as input, and prints all pairs of digits within the number that sums into a per-specified number.
My code is:
def f(n,num):
s = str(n)
l =
for digit in s:
l.append(digit)
for i in range(len(l)):
for j in range(len(l)):
if i != j:
if (int(l[i]) + int(l[j]) == num):
print(l[i]," ",l[j])
It works fine, but every pair is printed twice. I couldn't find a way to remove the duplicates and print every pair only once.
Can you assist ? Thank you.
for j in range(len(l)):
for j in range(i+1,len(l)):
Thank you, works now.
– user2899944
Jun 30 at 7:44
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for j in range(len(l)):=>for j in range(i+1,len(l)):and you can drop the i != j test– Jean-François Fabre
Jun 30 at 7:30